`y = sin(pix)^2` Find the derivative of the function.

Textbook Question

Chapter 2, 2.4 - Problem 47 - Calculus of a Single Variable (10th Edition, Ron Larson).
See all solutions for this textbook.

1 Answer | Add Yours

sciencesolve's profile pic

sciencesolve | Teacher | (Level 3) Educator Emeritus

Posted on

You need to use the chain rule to evaluate the derivative of the function, such that:

`y' = (sin(pi*x)^2)'*((pi*x)^2)'*(pi*x)'`

`y' = (cos(pi*x)^2)*(2(pi*x))*pi`

`y' = 2pi^2*x(cos(pi*x)^2)`

Hence, evaluating the derivative of the function, using the product rule, yields `y' = 2pi^2*x(cos(pi*x)^2)` .

We’ve answered 318,991 questions. We can answer yours, too.

Ask a question