`y = sin(pix)^2` Find the derivative of the function.

Textbook Question

Chapter 2, 2.4 - Problem 47 - Calculus of a Single Variable (10th Edition, Ron Larson).
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sciencesolve | Teacher | (Level 3) Educator Emeritus

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You need to use the chain rule to evaluate the derivative of the function, such that:

`y' = (sin(pi*x)^2)'*((pi*x)^2)'*(pi*x)'`

`y' = (cos(pi*x)^2)*(2(pi*x))*pi`

`y' = 2pi^2*x(cos(pi*x)^2)`

Hence, evaluating the derivative of the function, using the product rule, yields `y' = 2pi^2*x(cos(pi*x)^2)` .

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