**Note:- 1) If y = sinx ; then dy/dx = cosx**

**2) If y = cotx ; then dy/dx = -cosec(^2)x**

Now,

y = sin(cotx)

Let g(x) = cotx..............(inner function)

and f(x) = sinx ...........(outer function)

Thus, f(g(x)) = sin(cotx)...................answer

Now, y = sin(cotx)

thus, dy/dx = y' = cos(cotx)*[-cosec^(2)x]

or, dy/dx = y' = -[cosec^(2)x]*[cos(cotx)]

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