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`y sin(2x) = x cos(2y), (pi/2, pi/4)` Use implicit differentiation to find an equation of the tangent line to the curve at the given point.

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Note:- 1) If  y = sinx ; then dy/dx = cosx 

2) If y = cosx ; then dy/dx = -sinx

3) If y = u*v ; where both u & v are functions of 'x' , then

dy/dx = u*(dv/dx) + v*(du/dx)

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