1 Answer | Add Yours
The slope of the tangent is equal to the derivative of the equation of the curve at the given point.
`dy/dx = secx.tanx`
The slope of the tangent is equal to `2sqrt3.`
The equation of the tangent is equal to `y-2=2sqrt3(x-pi/3)`
that is `2sqrt3x-y=(2pi)/sqrt3-2`
We’ve answered 318,935 questions. We can answer yours, too.Ask a question