`y = sec^2 (x), 0<=x<=(pi/3)` Use a graph to give a rough estimate of the area of the region that lies beneath the given curve. Then find the exact area.
Refer the graph in the attached image.
From the graph,
Area of the region beneath the curve `~~` 4/10(Area of the Rectangle)
Area of the region=`~~(4/10)(pi/3*4)`
Area of the region`~~1.676`
Exact Area of the region=`int_0^(pi/3)sec^2(x)dx`