`y = sec^2(m theta)` Find the derivative of the function.
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Note:- 1) If y = secx ; then dy/dx = sex*tanx
2) If y = x^n ; then dy/dx = n*{x^(n-1)} ; where n = real number
3)If y = a*x ; then dy/dx = a ; where a = constant
Now,
Let theta be represented as 'x' ; then
y = sec^2(mx)
dy/dx = y' = [2*sec(mx)]*[sec(mx)*tan(mx)]*[m]
or, dy/dx = 2*m*tan(mx)*[sec^2(mx)]
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