`y = ln(sec(x) + tan(x))` Find y' and y''.

Textbook Question

Chapter 3, 3.6 - Problem 26 - Calculus: Early Transcendentals (7th Edition, James Stewart).
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hkj1385 | (Level 1) Assistant Educator

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`y = ln[secx + tanx]`

`dy/dx = {1/(secx + tanx)}*{secx*tanx + sec^2(x)`

` ` `dy/dx = {secx*(secx + tanx)}/(secx+tanx) = secx`

`(d^2y)/dx^2 = secx*tanx`

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