`y = ln| cos(ln(x)) |` Differentiate the function.

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hkj1385 eNotes educator| Certified Educator

Notes:- 1) If y = lnx ; then dy/dx = 1/x

2) If y = cosx, then dy/dx = -sinx

3) If 'y' is a function which contains sub-functions, then the last function is differentiated first,then the second last and so on


the given question is 

`y = ln[cos(ln(x)]`

Thus, `dy/dx = [1/cos(lnx)]*[-sin(lnx)]*(1/x)`

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