`y = e^x, y = sqrt(x) + 1` Use a graph to estimate the x-coordinates of the points of intersection of the given curves. Then use this information and your calculator to estimate the volume of...
`y = e^x, y = sqrt(x) + 1` Use a graph to estimate the x-coordinates of the points of intersection of the given curves. Then use this information and your calculator to estimate the volume of the solid obtained by rotating about the y-axis the region enclosed by these curves.
`y=sqrtx + 1`
The graph of these two equations are:
(Green curve graph of `y=e^x` . And blue curve is the graph of `y=sqrt(x) + 1` .)
Base on the graph, the two curve intersect at `x=0` and `x~~0.56` .
To solve for the volume of the solid formed when the bounded region is rotated about the y-axis, apply the method of cylinder. Its formula is:
To determine the radius and height of the cylindrical shell, refer to the figure below. Its radius and height are:
`r = x`
`h=y_(upper) - y_(lower)=sqrtx + 1 - e^x`
Plug-in them to the formula of volume.
`V=int_0^0.56 2pi *x*(sqrtx + 1-e^x) dx`
`V= 2pi int _0^0.56 (x^3/2 + x - xe^x) dx`
Take the integral of each term.
`V= 2pi (int_0^0.56dx + int_0^0.56 xdx - int_0^0.56 xe^xdx)`
For the first two integral, apply the formula `int x^n dx = x^(n+10)/(n+1)` .
And for the third integral, apply integration by part `int u dv = uv - int vdu` .
`V=2pi( (2x^(5/2))/5+x^2/2 - (xe^x-e^x))|_0^0.56`
`V = 2pi ( (2x^(5/2))/5+x^2/2 - xe^x+e^x)|_0^0.56`
`V = 2pi [( (2*0.56^(5/2))/5+0.56^2/2-0.56*e^0.56+e^0.56)- ((2*0^(5/2))/2+0^2/2-0*e^0+e^0)]`
Therefore, the volume of the solid formed is 0.1317 cubic units.