# `y = e^x / x , (1, e)` Find an equation of the tangent line to the given curve at the specified point.

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Student Comments

balajia | Student

The slope of the tangent at a point is equal to the derivative of the given function at that point.

`(dy)/(dx)=e^x/x-e^x/x^2`

At (1,e) the derivative is equal to 0.

The slope of the tangent is equal to zero.

The equation of tangent is equal to y-e=0(x-1)

that is y=e.

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