`y = e^x cos(x), (0, 1)` Find an equation of the tangent line to the curve at the given point.

1 Answer

Educator Approved

Educator Approved
balajia's profile pic

balajia | College Teacher | (Level 1) eNoter

Posted on

The slope of tangent  to `y=e^xcosx` at (0,1) = `dy/dx` at (0,1)

 `dy/dx = e^x(cosx-sinx)`

Slope is equal to 1.

The equation of the tangent is equal to `y-1=1(x-0).`

That is `x-y+1=0.`