# `y = e^x cos(x), (0, 1)` Find an equation of the tangent line to the curve at the given point.

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Student Comments

balajia | Student

The slope of tangent to `y=e^xcosx` at (0,1) = `dy/dx` at (0,1)

`dy/dx = e^x(cosx-sinx)`

Slope is equal to 1.

The equation of the tangent is equal to `y-1=1(x-0).`

That is `x-y+1=0.`

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