# `y = e^sqrt(x)` Write the composite function in the form f(g(x)). Identify the inner function u = g(x) and the outer function y =f(u). Then find the derivative dy/

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### 2 Answers

**Note:- 1) If y = e^{ax} ; then dy/dx = a*e^(ax)**

**2) If y = sqrt(x) ; then dy/dx = 1/{sqrt(x)}**

**3) If y = x^n ; then dy/dx = n*x^(n-1)**

Now, y = e^{sqrt(x)}

Let g(x) = sqrt(x) ..............(inner function)

and, f(x) = e^x ............(outer function)

Thus, f(g(x)) = e^{sqrt(x)}.................answer

Now, y = e^{sqrt(x)}

thus, y' = dy/dx = [1/{2*sqrt(x)}]*[e^{sqrt(x)}]

The given function is `y=e^(sqrt(x))`

This is in the form `y=f(g(x))`

Here `f(x)=e^x and g(x)=sqrt(x)`

`dy/dx=e^(sqrt(x))(1/(2sqrt(x)))`

=`(e^(sqrt(x)))/(2sqrt(x))`