`y = 5lnx` Determine whether the function is a solution of the differential equation `y^((4)) - 16y = 0`

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`y = 5ln(x)`

`y' = 5/x`




so we have to check whether` y^((4)) -16y=0`

`y'''' -16y=-30/x^4 -16(5ln(x)) != 0  ` 

So it's not a solution to the differential equation.

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