If |y| = 4x^2 + 3x - 1 what is the x and y intercept of the graph.

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The x and y intercepts of the graph given by the equation |y| = 4x^2 + 3x - 1 has to be determined.

When the graph intersects the y-axis, the value of x = 0.

|y| = 4*0 + 3*0 - 1 = -1

But |y| can only take on values greater than or equal to 0. The graph of |y| = 4x^2 + 3x - 1 does not have any y intercepts.

At the x-intercepts, the value of y = 0

0 = 4x^2 + 3x - 1

=> 4x^2 + 4x - x - 1 = 0

=> 4x(x + 1) - 1(x + 1) = 0

=> (4x - 1)(x + 1) = 0

=> x = 1/4 and x = -1

The x intercepts of the graph is at 1/4 and -1.

The graph of |y| = 4x^2 + 3x - 1 does not have any y-intercepts and the x intercepts are at 1/4 and -1.

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