y=4+cotx-2cscx: Find the equation for the tangent at x=pi/2 y=4+cotx-2cscx, x = pi/2   Thank you very much in advanced :DD

Expert Answers

An illustration of the letter 'A' in a speech bubbles

To find the equation of the tangent line, determine the point of tangencey and its slope.

To do so, susbtitute `x=pi/2` to the equation of the curve.


Note that `cot(pi/2)=0` and `csc(pi/2)=1` .


Hence, the point of tangency is `(pi/2,2)` .

The slope of the tangent line is the same as the slope of the curve at the point of tangency.

To determine the slope of the curve take the derivative of y.



Note that `(c)'=0`  (where c is a constant) , `(cotu)=-csc^2u*u'` and `cscu=-cscucotu*u'` .

`y'=0-csc^2x*1 -2(-cscxcotx*1)=-csc^2x+2cscxcotx`

Subsitute `x=pi/2` .



Hence, the slope of the tangent line is -1.

Now that the slope of the line and point of tangency is known, apply the point-slope formula of a line.


where m is the slope and `(x_1, y_1)` is the given point.

Substitute the slope m=-1 and the point `(pi/2,2)` .






Hence, the equation of the tangent line is `y=-x+(4+pi)/2` .

Approved by eNotes Editorial Team

Posted on

Soaring plane image

We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

  • 30,000+ book summaries
  • 20% study tools discount
  • Ad-free content
  • PDF downloads
  • 300,000+ answers
  • 5-star customer support
Start your 48-Hour Free Trial

Already a member? Log in here.

Are you a teacher? Sign up now