We can use the substitution method to solve for the solution of the given equations.

if we substitute `y=-3x+8` to the equation `y=-5x-2` , we get

`y=-5x-2`

`(-3x+8)=-5x-2`

`-3x+5x=-2-8`

`2x=-10`

`x=-5`

Then if we substitute the value of x in either of the two equation. Let's say at `y=-3x+8` ....

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We can use the substitution method to solve for the solution of the given equations.

if we substitute `y=-3x+8` to the equation `y=-5x-2` , we get

`y=-5x-2`

`(-3x+8)=-5x-2`

`-3x+5x=-2-8`

`2x=-10`

`x=-5`

Then if we substitute the value of x in either of the two equation. Let's say at `y=-3x+8` . We obtain

`y=-3(-5)+8`

`y=15+8`

`y=23`

In other words, the point `(-5,23)` is a solution or intersection of the graphs of the two functions.