# y=3(x-4)+1 i would like to know the slope and the point

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Given an equation in the form of

`y = mx + b`

the slope is given by *m*, and the y-intercept is given by *b*.

We'll transform the given equation into that form:

`y = 3(x - 4) + 1`

Multiply each term in the parentheses by 3:

`\implies y = 3x - 12 + 1`

Next, combine like terms by adding 1 to -12:

`\implies y = 3x - 11`

**Therefore the slope of the given equation is 3 and the y-intercept is -11.**

y=3(x-4)+1

Recall that the point-slope formula is:

y - y1 = m(x - x1) where m is the slope and (x1, y1) is a point.

Its simple step of algebra to change what you have into that form. Subtract 1.

y - 1 = 3(x - 4)

Its now readily apparent that you have a slope of 3 and one point on it is (4, 1)