If y-3=7 and x+3y=6 then x=?Show your work.

If y-3=7 and x+3y=6 then x=?

First let's find what " y " equals

y - 3 = 7 add 3 on both sides

By adding, you should get

y = 10 which is what " y " equals 

Now plug 10 into the equation

x + 3 ( 10 ) = 6 multiply 3 with 10

By multiplying,  you should get

x + 30 = 6 now subtract 30 on both sides

By subtracting, your equation should look like

x = -24 which Is your answer

If y-3=7 and x+3y=6 then x=

we need ot get the unkown variables by themselves, and usually you start with the equation that only has one unknown variable, wheich would be y-3=7

you add three to both sides so the -3 goes away leaving you with the value of y

y=10

then you plug this value into the other equation x+3y=6

to give you X+ 3(10) = 6

X+30=6

then you do the same thing, you try to get the 30 onto the right side by subtracting 30 from both sides so it gives you the value of X

X= -24

 y-3=7 and x+3y=6 then x=

y - 3 = 7

   +3   +3

y=10

plug in the number in the second problem

x+3(10)=6

x+30=6

  -30   -30

x= -24

If y-3=7 and x+3y=6 then x=?

First solve for y because we have enough information for that. 

y = 3 + 7 = 10

plug into the other equation: 

x + 3(10) = 6

x + 30 = 6

x = 6 - 30 = -24

y-3=7

y-3+3=7+3

y=10

x+3y=6

x+3(10)=6

x+30=6

x+30-30=6-30

x=-24

Well

x+3y=6   and y-3=7

(+3)y-3=7(+3)

y=10

x+3(10)=6

x+30=6

x= -24