`y=(2x)/(x^2-1)` Graph the function.
We are asked to graph the function `y=(2x)/(x^2-1) ` :
Factoring the denominator we get:
The graph has vertical asymptotes at x=1 and x=-1. The horizontal asymptote is y=0.
The y-intercept is 0 as is the only x-intercept.
The first derivative is ` y'=(-2(x^2+1))/((x^2-1)^2) ` so the function is decreasing on its domain.