Notes:- 1) If y = x^n ; then dy/dx = n*x^(n-1)

2) If a function to be differentiated contains sub-functions, then the differentiation of the last function is done first and so on

Now, given

y = {2*(x^3) + 5}^4

Let f(x) = x^4 ..........(outer function)

and g(x) = {2*(x^3) + 5}.........(inner function)

Thus, f(g(x)) = {2*(x^3) + 5}^4.............answer

Now,

y = {2*(x^3) + 5}^4

thus, dy/dx = [4*{2*(x^3) + 5}^3]*[6*x^2]

or, dy/dx = {24*(x^2)}*[{2*(x^3) + 5}^3]

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