`y = 2^(3^(x^2))` Find the derivative of the function.

1 Answer

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gsenviro | College Teacher | (Level 1) Educator Emeritus

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`y'=d/dx ((2^3)^(x))^2 = ln(2) * ((2^3)^x)^2 d/dx ((3^x)^2)`

`= ln(2) ln(3) *(3^x)^2 * d/dx (x^2) * ((2^3)^x)^2`

`= ln(2)* ln(3) * 2x * (3^x)^2 * ((2^3)^x)^2 `

`= ln(2)*ln(3)*x*(3^x)^2 * 2*((2^3)^x)^2`

Hope this helps.