`y^2=-10x` Graph the equation. Identify the focus, directrix, and axis of symmetry of the parabola.

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Let `y^2=4px`  be equation of parabola. Then equation of directrix is `x=-p` coordinates of focus are `(p,0)` and axis of symmetry is `x`-axis.

In this case equation of parabola is

`y^2=-10x`

Therefore,

`4p=-10`

Divide by 4 in order to obtain `p.`

`p=-10/4=-5/2`

Using the facts stated at the beginning we can write the equation...

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Let `y^2=4px`  be equation of parabola. Then equation of directrix is `x=-p` coordinates of focus are `(p,0)` and axis of symmetry is `x`-axis.

In this case equation of parabola is

`y^2=-10x`

Therefore,

`4p=-10`

Divide by 4 in order to obtain `p.`

`p=-10/4=-5/2`

Using the facts stated at the beginning we can write the equation of directrix and coordinates of focus.

Directrix is the line `x=5/2,` focus is the point `(-5/2,0)` and axis of symmetry is `x`-axis.                        

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