Using the exponential function rule:

`[a^(u(x))]' = ln(a)*a^(u(x))*u'(x) `

we get

`y' = [10^(1-x^2)]'`

`= ln(10)*10^(1-x^2)*d/dx(1-x^2)`

`=-2x*ln(10)*10^(1-x^2)`

Hope this helps.

Using the exponential function rule:

`[a^(u(x))]' = ln(a)*a^(u(x))*u'(x) `

we get

`y' = [10^(1-x^2)]'`

`= ln(10)*10^(1-x^2)*d/dx(1-x^2)`

`=-2x*ln(10)*10^(1-x^2)`

Hope this helps.