`y = 1 / (s + k*e^s)` Differentiate.

Textbook Question

Chapter 3, 3.2 - Problem 18 - Calculus: Early Transcendentals (7th Edition, James Stewart).
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balajia | College Teacher | (Level 1) eNoter

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`y(s)=(s+ke^s)^(-1)`

`y'(s)=(-1)(s+ke^s)^(-2)(1+ke^s)`

`y'(s)=-(1+ke^s)/(s+ke^s)^(-2)`

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