`y = 1 / (s + k*e^s)` Differentiate.

balajia | Student

`y(s)=(s+ke^s)^(-1)`

`y'(s)=(-1)(s+ke^s)^(-2)(1+ke^s)`

`y'(s)=-(1+ke^s)/(s+ke^s)^(-2)`

``

``

Access hundreds of thousands of answers with a free trial.

Start Free Trial
Ask a Question