`y = 1/(ln(x))` Differentiate the function.
You need to differentiate the function with respect to x, using the quotient rule, such that:
`f'(x) = (1/(ln x))'`
`f'(x) = (1'*(ln x) - 1*(ln x)')/(ln^2 x)`
`f'(x) = (0*ln x - 1/x)/(ln^2 x)`
`f'(x) = -1/(x*ln^2 x)`
Hence, evaluating the derivative of the given function, yields` f'(x) = -1/(x*ln^2 x).`
Differentiate the function.
Rewrite this as:
We can take the derivative by power rule and chain rule. Chain rule is the derivative of the inner function.
`y'= -(ln(x))^-2 * (1/x)`
This simplifies to: