# `y = (1/2)sin(pi*x/3)` Find the period and the amplitude

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### 2 Answers

Formula for amplitude: if y = a *sin *bx, amplitude is the absolute value of a

**Amplitude of .5**

Formula for period: if y = a *sin *bx, period is 2pi/b

Here, this gives us 2pi/pi/3, which can be rearranged to

`2pixx3/pi`

Pi cancels and gives 2x3

**Period of 6**

### User Comments

`y = (1/2)sin(pix/3)`

the general form is `y= a sin(bx)`

on comparing with the above equation with the general form we get

the amplitude is `|a| = (1/2)`

and the period for the sin is `(2* pi) /|b| = (2pi)/(pi/3) = 6`