Given the equation of a circle"
x^2 + y^2 - 4x +6y -36 = 0
We will use completing the square method to rewrite the equation into the form:
(x-a)^2 + (y-b)^2 = r^2 where (a,b) is the center and r is the radius.
Let us rewrite the terms.
==> x^2 - 4x + y^2 + 6y = 36
Now we will complete the square for both x^2 ands y^2.
We will add [( coefficient of x)/2]^2 and...
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