x(x-40)(3x+2)= 240 can you find the value of X and show me how to get it
The equation to be solved is x(x-40)(3x+2)= 240
=> (x^2 - 40x)(3x + 2) = 240
=> 3x^3 - 120x^2 + 2x^2 - 80x = 240
=> 3x^3 -198x^2 - 80x = 240
=> 3x^3 -198x^2 - 80x - 240 = 0
It is not possible to solve for x using this equation except by using the formula for roots of a cubic equation which is given at the link provided below.
As the process of working out the roots is a very tedious one I have only provided the final results.
The roots of the equation are: 66.41, -0.2098 + i*1.077 and -0.2098 - i*1.077