`x = sec(1/y)` Find `dy/dx` by implicit differentiation.

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Chapter 2, 2.5 - Problem 16 - Calculus of a Single Variable (10th Edition, Ron Larson).
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hkj1385 | (Level 1) Assistant Educator

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`x = sec(1/y)`

``Differentiating both sides w.r.t 'x' we get

`1 = sec(1/y)tan(1/y)*(-1/y^2)*(dy/dx)`

`or, dy/dx = (-y^2)/(sec(1/y)*tan(1/y))`

``

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