**Note:- 1) If y = e^x ; then dy/dx = e^x**

**2) If y = x^n ; then dy/dx = n*x^(n-1) ; where 'n' = real number**

**3) If y = u*v ; where both u & v are functions of 'x' ; then **

**dy/dx = u*(dv/dx) + v*(du/dx)**

Now, the given function is :-

x*(e^y) = x - y

Differentiating both sides w.r.t 'x' we get

x*(e^y)*(dy/dx) + (e^y) = 1 + (dy/dx)

or, [x*(e^y) - 1]*(dy/dx) = [1 - (e^y)]

or, dy/dx = [1 - (e^y)]/[x*(e^y) - 1]

## We’ll help your grades soar

- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support

Already a member? Log in here.

Are you a teacher? Sign up now