`x e^y = x - y` Find `(dy/dx)` by implicit differentiation.

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Note:- 1) If y = e^x ; then dy/dx = e^x

2) If y = x^n ; then dy/dx = n*x^(n-1) ; where 'n' = real number

3) If y = u*v ; where both...

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`xe^y=x-y`

Differentiating both sides with respect to x.

`e^y+xe^y(dy/dx)=1-dy/dx`

`(1+xe^y)(dy/dx)=1-e^y`

`dy/dx=(1-e^y)/(1+xe^y) `

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