`x = e^(-5/6)` Evaluate `g(x) = ln(x)` at the indicated value of `x` without using a calculator.

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Textbook Question

Chapter 3, 3.2 - Problem 63 - Precalculus (3rd Edition, Ron Larson).
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loves2learn | (Level 3) Salutatorian

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Plug in the value for x in `g(x) `

`g(x)=lne^(-5/6) `

Bring down the exponent

`=(-5/6)lne `

Remember that `lne=1 `


`g(x)=-5/6 `

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