`x = e^(-5/2)` Evaluate `g(x) = ln(x)` at the indicated value of `x` without using a calculator.

Textbook Question

Chapter 3, 3.2 - Problem 64 - Precalculus (3rd Edition, Ron Larson).
See all solutions for this textbook.

1 Answer | Add Yours

loves2learn's profile pic

loves2learn | (Level 3) Salutatorian

Posted on

Plug in the value of x in `g(x) `

`g(x)=lne^(-5/2) `

Bring down the exponent

`=(-5/2)lne `

Remember that `lne=1 `

Simplify,

`g(x)=-5/2 `

We’ve answered 318,946 questions. We can answer yours, too.

Ask a question