If x is an angle in standard position with point A(-3 , 4) on the terminal side, then sec(x) =

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We have that x is an angle in standard position with point A(-3 , 4) on the terminal side.

sec x = 1/ cos x

cos x = adjacent side / hypotenuse.

Here the adjacent side is -3 and the hypotenuse is sqrt ((-3^2) + 4^2) = sqrt ( 9 + 16) = sqrt 25 = 5.

The value of cos x = -3/5

Therefore the required value of sec x is -5/3

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We will draw a line between the point (-3, 4) and the origin point.

Then angle x located between the line and the x-axis.

Then, we hace formed a right angle triangle where the base = 3, the height = 4 .

Now we will calculate the length of the line which is the hypotenuse.

==> The hypotenuse = sqrt(3^2 + 4^2 ) = sqrt25 = 5

Now we will determine sec(x).

We know that sec(x) = 1/cos(x)

But cos(x) = adjacent / hypotenuse.

==> cos(x) = 3/5

But the angle is in the 4th quadrant.

then cos(x) = -3/5

==> sec(x) = -5/3

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