x^3+2x^2-x-2=0 solve for x
Substitute with 1:
Then 1 is one of the function's roots.
Then (x-1) is one of the factors.
Now divide the function by (x-1).
Then the roots are:
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x^3 + 2x^2 - x - 2 = 0
We factorise the left hand side of the equation as follows:
x^3 + 2x^2 - x - 2
= x^2(x + 2) - 1(x + 2)
= (x^2 - 1)(x +2)
= (x + 1)(x - 1)(x + 2)
x = -1, 1, and -2