If x^2+ kx - 6 = (x - 2)(x + 3), then k = ?
- print Print
- list Cite
Expert Answers
calendarEducator since 2010
write12,551 answers
starTop subjects are Math, Science, and Business
We are given that x^2+ kx - 6 = (x - 2)(x + 3)
Now x^2+ kx - 6 = (x - 2)(x + 3)
=> x^2 + kx - 6 = x^2 -2x + 3x - 6
=> x^2 + kx - 6 = x^2 + x - 6
canceling the common terms
=> kx = x
=> k = 1
Therefore k = 1
Related Questions
- What is k if f(x)=x^2-kx-3 and f(2)=9 ?
- 1 Educator Answer
- Given f(x) = k(2+x), find the value of k if f^-1 (-2) = -3
- 1 Educator Answer
- How do i find k when x^3+kx^2+2x-3 is divided by X+2 and the remainder is 1
- 1 Educator Answer
- `f(x) = kx^2, y = -2x + 3` Find k such that the line is tangent to the graph of the function.
- 1 Educator Answer
- Find the value of k if x^2 + kx - 6 = (x - 2)(x + 3).
- 2 Educator Answers
calendarEducator since 2008
write3,662 answers
starTop subjects are Math, Science, and Social Sciences
Given that x^2 + kx - 6 = (x-2)(x+3)
We need to find k.
First we will need to open the brackets on the left side and then compare the terms.
==> x^2 + kx -6 = x^2 -2x + 3x - 6
==> x^2 + kx -6 = x^2 + x -6
Now we will add 6 to both sides.
==> x^2 + kx = x^2 + x
Now we will subtract x^2
==> kx = x
Now we will subtract x from both sides.
==> kx -x = 0
Now we will factor x.
==> x (k-1) = 0
x can not be zero.
Then k-1 = 0 ==> k= 1
Then the value of k is 1.
To find k if x^2+ kx - 6 = (x - 2)(x + 3).
Solution:
We expand the right side and solve the equation.
x^2+kx-6 = (x-2)(x+3).
x^2+kx-6 = x(x+3)-2(x+3).
x^2+kx-6 = x^2+3x-2x-6.
x^2+kx-6 = x^2 +x -6.
Subtract x^2-6 from both sides:
kx = x.
So k = 1.
Student Answers