# x+2/4=x-1

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x+2/4=x-1

Well first you have to take out the divided by 4, so for that you multiply both sides by 4

((x+2)/4) x 4= 4x-4

x+2=4x-4

Now you would move all the variables on one side

4x-x=2+4

Now simplify the equation and you would be able to get

3x=6

To get the final answer just divide by 3 and **x=2**

**QUESTION:-**

**x+2/4=x-1**

**SOLUTION:-**

`(x+2)/4=(x-1)`

As always we will use the PEMDAS/BODMAS order of operations through which first we open brackets, then multiply then divide then add and at last subtract.

Multiply both sides with 4;

`{(x+2)/4}*4=(x-1)*4`

`x+2=(x-1)*4`

Open RHS bracket by multiplying both the values with 4;

`x+2=4x-4`

`2+4=4x-x`

`6=3x`

`3x=6`

Now divide both sides with 3;

`(3x)/3=6/3`

`x=2`

Therefore the answer is 2.

Hence it is Solved!

`(x + 2)/4 = x - 1`

To simplify this we need to follow the order of operations, i.e BODMAS / PEMDAS, first we need to multiply both sides by 4,

`(x + 2)/4 * 4 = 4(x-1)`

` `

`x + 2 = 4x - 4`

`x + 2 - 2 = 4x - 4 - 2`

`x - 4x = 4x - 4x - 6`

`-3x = -6`

`-3x/-3 = -6/-3`

`x = 2 Answer.`

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The equation (x+2)/4=x-1 has to be solved for x.

(x+2)/4=x-1

Multiply both sides by 4

x + 2 = 4*(x - 1)

x + 2 = 4x - 4

Add -2 to both the sides

x = 4x - 6

Subtract 4x from both the sides

-3x = -6

Divide both the sides by -3

x = 2

The solution of the equation (x+2)/4=x-1 is x = 2

x+2/4=x-1

Given

`(x+2)/4=x-1`

`=> ((x+2)/4)xx4=(x-1)xx4`

`=> x+2=4x-4`

`=>x-x+2+4=4x-4+4-x`

`=>6=3x`

`=>6/3=(3x)/3`

`=>2=x`

Thus x=2.