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`(x - 2)^2 = ln(x)` Use Newton's method to find all roots of the equation correct to six decimal places.

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See the attached graph. The curve of the function intersects the x-axis at x `~~` 1.4 and 3. These can be used as initial approximates. Iterate until six digit decimal places are same.


For x_1=1.4





For x_1=3






Roots of the equation are 1.412391 , 3.057103

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