Let `x^2=4py` be equation of parabola. Then equation of directrix is `y=-p` coordinates of focus are `(0,p)` and axis of symmetry is `y`-axis.

In this case the equation of parabola is

`x^2=12y`

Therefore,

`4p=12`

`p=3`

Using the facts stated above we can write equation of directrix and coordinates of focus.

**Directrix is line with equation `y=-3` focus is the point with coordinates `(0,3)` and axis of symmetry is `y`-axis.**

## See eNotes Ad-Free

Start your **48-hour free trial** to get access to more than 30,000 additional guides and more than 350,000 Homework Help questions answered by our experts.

Already a member? Log in here.

**Further Reading**