if (x+1) and (x+2) are both factors of x^3+ax^2+bx-10 , find the values of a and b help !

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As we have (x+1) (x+2) we can use substitution to solve and find the third factor. Remember that these factors are true when y or f(x) = 0

x^3+ax^2+bx-10 Substitute the two values you have (x=-1; x= -2)

`f(-1)= (-1)^3 + a(-1)^2 + b(-1) - 10`   

`therefore 0= -1 +a - b - 10` multiply this line by 2. You'll see...

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