If (x+1),3x,(4x+2) are consecutive terms of an A.P, then what is the value of x?

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We are given that (x+1), 3x, (4x+2) are in A.P. As they are A.P., consecutive terms have a common difference.

So 4x + 2 - 3x = 3x - x - 1

=> 4x - 3x + 2 = 2x - 1

=> x + 2 = 2x - 1

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We are given that (x+1), 3x, (4x+2) are in A.P. As they are A.P., consecutive terms have a common difference.

So 4x + 2 - 3x = 3x - x - 1

=> 4x - 3x + 2 = 2x - 1

=> x + 2 = 2x - 1

=> 2x - x = 2 + 1

=> x = 3

Therefore if x = 3, (x+1), 3x, (4x+2) are in A.P

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