Write the standard form of the quadratic function that has vertex (-2, 5) and whose graph passes through (0, 9)
1 Answer
justaguide | College Teacher | (Level 2) Distinguished Educator
A quadratic equation with vertex (-2, 5) is : y = a(x + 2)^2 + 5
As it passes through (0, 9), 9 = a(0 + 2)^2 + 5
=> 9 = 4a + 5
=> a = 1
The equation of the quadratic function is y = (x + 2)^2 + 5
=> y = x^2 + 4x + 9
The standard form of the quadratic function with vertex (-2, 5) and passing through (0, 9) is y = x^2 + 4x + 9