You should remember that the standard form of equation of parabola is given by  `ax^2 + bx + c = y` .

Supposing that the equation provides the vertex `V(-3,-2)`  and the leading coefficient `a = 5` , you may write the vertex form of equation of parabola such that:

`y = a(x - h)^2 + k`

h, k are coordinates of vertex of parabola

`y = 5(x + 3)^2 - 2 `

You need to expand the binomial to convert the vertex form of parabola in standard form such that:

`y = 5(x^2 + 6x + 9) - 2 => y = 5x^2 + 30x + 45 - 2`

`y =5x^2 + 30x + 43`

Hence, evaluating the standard form of equation of parabola, under the given conditions, yields `y = 5x^2 + 30x + 43` .