# Write the standard equation of a line that passes through the point (1,4) and it has the slope m=1/4.

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The equation of a line passing through a point (a, b) and with slope m is: (y - b)/(x - a) = m

Substituting the values we have here:

(y - 4)/(x - 1) = 1/4

=> 4(y - 4) = x - 1

=> 4y - 16 = x - 1

=> x - 4y + 15 = 0

**The required equation of the line is x - 4y + 15 = 0**

First, we'll recall the standard equation form:

y = mx + n, where m is the slope of the line and n represents the y intercept.

The equation of the line that is passing through a point and it has a given slope, is;

y - 4 = (1/4)*(x - 1)

We'll remove the brackets;

y - 4 = x/4 - 1/4

We'll add 4 both sides:

y = x/4 + 4 - 1/4

y = x/4 + 15/4

**The requested standard form of the equation of the line is: y = x/4 + 15/4.**