Your question is already in slope-intercept form. slope-intercept looks like this:

y = mx + b

which looks like yours with m = 1/2 and b = 1. If instead you are supposed to transform the equation into a different form, for example the point-intercept form, this is straightforward.

The point-intercept form takes this shape:

(y-y0) = m(x - x0)

This form is useful when you already know the slope, m, and a point P = (x0, y0) that the line passes through. In your case you know P = (-5, -4), and you know that m = 1/2.

y - -4 = 1/2(x - -5)

y + 4 = 1/2(x + 5) --> slope-intercept form.

You can verify that this is the same equation as y = 1/2x + 1 :

y = 1/2x + 5 - 4

y = 1/2x + 1

(-5,-4), y=1/2x+1

You are already in slope intercept form. Recall that the slope intercept form is

y = mx + b (where m is your slope, and by is the y-intercept)

I believe you're looking for a point slope form:

y - y1 = m(x - x1)

Which is fairly simple; just plug in!

y - (-4) = 1/2(x - (-5))

which simplifies to:

y + 4 = .5(x + 5)