Write as a simplified logarithm: 6 (log c)/log a + 5 loga d - 7 loga b Note: The letter "a" in 5 loga d and -7 loga b is a small subscript "a" whereas the letter "a" in 6 log c / log a is a normal a.
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We have to simplify : 6 (log c/log a) + 5 log(a) d - 7 log(a) b
Now we use the relation that log(a)b = log b / log a
6 (log c/log a) + 5 log(a) d - 7...
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