You should use the compound interest formula such that:

`A = P(1 + r/n)^(nt)`

You should know that P represents the amount invested, r represents the annual rate of interest, the number of time the interest is compounded/year.

You should substitute 5000 for P, `6/100 = 0.06 ` for r, 2 for n such that:

`A = 5000(1 + 0.06/2)^(2t)`

You may give values to t such that:

t = 1 year =>`A = 5000*(1.03)^2`

`A = 5304.5`

t = 2 years => `A = 5000*(1.03)^4=gtA = 5627.54405`

Hence, using the given values, the sequence may be formed for different values of t such that: `A = 5304.5(t=1year); A = 5627.54405(t=2years).` (remember that n represents the number of time the interest is compounded, hence `n=2`  because the problem provides the information that the interest is compounded semi-annually).