# Write the point-slope form of the equation passing through (5, -1) with a slope of 6. A. y-1=6(x+5) B. y+5=6(x-1) C. y+1=6(x-5) D. y-5=6(x+1)

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The slope intercept form is like this.

`y = mx+c`

It is given that our line has slope of 6.

`y = 6x+c`

Then this line passes through `(5,-1)` .

`-1 = 6xx5+c`

`c = -31`

So the slope intercept form is;

`y = 6x-31`

By rearranging the above;

`y = 6x-30-1`

`y+1 = 6(x-5)`

**So the answer is C.**

**Sources:**

Linear equations can be written in different ways we usually list three main forms:

1st slope-intercept: y=mx+b where m is the slope and b is the y-coordinate of the y-intercept.

2nd slope-point: y-y1=m(x-x1) where m is slope and (x1,y1) is a point on the line` `

3rd standard:Ax+By=C

In your case you are given a slope and a point, so we are in the second case. Hence y-(-1)=6(x-5), that simplifies into y+1=6(x-5). **Thus choice C.**

`(y-y_0)=m(x-x_0)`

so st passage fo the poin P with slope 6:

`y+1=6(x-5)`

Answer `C)`

(5, -1) with a slope of 6.

Plug this into the point slope formula:

y - y1 = m(x - x1) where m is the slope and (x1, y1) is the point.

This leaves you with:

y + 1 = 6(x - 5)

This matches answer choice C.