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The slope intercept form is like this.
`y = mx+c`
It is given that our line has slope of 6.
`y = 6x+c`
Then this line passes through `(5,-1)` .
`-1 = 6xx5+c`
`c = -31`
So the slope intercept form is;
`y = 6x-31`
By rearranging the above;
`y = 6x-30-1`
`y+1 = 6(x-5)`
So the answer is C.
Linear equations can be written in different ways we usually list three main forms:
1st slope-intercept: y=mx+b where m is the slope and b is the y-coordinate of the y-intercept.
2nd slope-point: y-y1=m(x-x1) where m is slope and (x1,y1) is a point on the line` `
In your case you are given a slope and a point, so we are in the second case. Hence y-(-1)=6(x-5), that simplifies into y+1=6(x-5). Thus choice C.
so st passage fo the poin P with slope 6:
(5, -1) with a slope of 6.
Plug this into the point slope formula:
y - y1 = m(x - x1) where m is the slope and (x1, y1) is the point.
This leaves you with:
y + 1 = 6(x - 5)
This matches answer choice C.
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