# Write a pair of negative integers whose difference gives 10 and whose sum is -10.

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Student Comments

neela | Student

Let n and m be the negative numbers. Let m < n. Then , the difference is:

n-m = 10 ...............(1) as given. And their sum is

n+m = -10..............(2)as given.

From (1) , n= m+10 and substitute this for n in eq(2):

(m+10)+m = -10.

2m+10 = -10.

2m = -10-10 = -20. So ,

m = -20. Or m = -20/2 =-10.

Therfore n = -n+10 = 0.

So the two numbers are -10 and 0. There are no other set of negative numbers satisfying the condition.