`(1+6x)/((4x-3)*(2x-5)) = (A/(4x-3))+(B/(2x+5)) `

`=> (1+6x) = A(2x+5)+B(4x-3) `

Equating the co efficient s of x and the constants we get the answer of A & B

`(1+6x)/((4x-3)(2x+5))=A/(4x-3)+B/(2x+5)`

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